Two persons Ram and Shyam wish to throw a ball at each other as shown in the figure. The maximum horizontal distance from the building where Ram can stand and still throw a ball at Shyam is d1.The maximum horizontal distance of Ram from the building where Shyam can throw a ball at Ram is d2. If both of them can throw the ball with a velocity of  2 g k , find  d 1 d 2 . Neglect the height of each person.



(1)  k + h k - h                            (2)  k - h k + h
(3)  2 k + h k - h                          (4)  2 k - h k + h

Dear student,For distance d1 the velocity 2gh will be substracted from the velocity 2gk as shyam is at height h above ram,so the distance will be less,d1=2gk-2ghd1=2g(k-h)similarly,d2=2gk+2ghd2=2g(k+h)d1d2=2g(k-h)2g(k+h)d1d2=(k-h)(k+h)Regards

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