two point charges 1.0 micro C and -0.25 micro coloumb are placed in air at a distance 0.40m from each other.find out at wich point on the line joining the two charges should a third charge be placed so that no force acts upon it?


Let third Q be placed at a point P from charge q1 (- 0.25 micro coulomb).

Condition for equilibrium, that is, no force acts upon third charge:

Attraction force between q1 and Q = Repulsion force between q2 and Q

Magnitude of charge, q1=0.25 μCMagnitude of charge, q2=1 μCHence, from Coulombs law,kq1Qx2=kq2Qd+x2d+xx2=q2q1d+xx=q2q11+dx=q2q1dx=q2q1-1x=dq2q1-1  =0.410.25-1 =0.41 =0.4 m (from charge of -0.25 micro coulomb)

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