two point charges of equal magnitude Q are placed at the separation of 5 cm such that the force acting - Science - Electricity

Question

two point charges of equal magnitude Q are placed at the separation
of 5 cm such that the force acting between them is 50 Newton then
find the magnitude of the charge

Vipra Mishra · Accepted Answer

Dear Student
F=QQ4πεor2=Q24πεor250=Q24πεo0
05250=9×109×Q2×400Q2=50400×9×109=0
0013108Q=0 037×10-4=3 7μC
Regards

two point charges of equal magnitude Q are placed at the separation of 5 cm such that the force acting between them is 50 Newton then find the magnitude of the charge