Two polaroids are kept crossed to each other. Now one of them is rotated through an angle of 450. The percentage of incident light now transmitted through the system is (ans:25%)

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  • -1
Let intensity be i.On passing through first Polaroid intensity reduces to half i.e i/2. On passing through second Polaroid intensity can be found by using malus law. I new = i/2cos^(phi/2) Given phi =45° I new = i/2(1/✓2)^2 I new = i/4. Now percentage of incident light transmitted is (1/4)100= 25%
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two polaroids are kept crowe weah other, one of them is rotated through an angle of 45 the percentage of incident light now transmitted through the system is
 
  • -2
Let intensity of unpolarised light is Io.after passing first Polaroid its intensity becomes Io/2 Now after rotating 45 intensity becomes Io/2cos'2(45) . Therefore intensity from second Polaroid is Io/4Io×100%= 25%
  • 1
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