Two radioactive elements R and S disintegrate as 
R → P + α; λR = 4.5 × 10–3 years–1
S → P + β; λS = 3 × 10–3 years–1Starting with number of atoms of R and S in the ratio of 2 : 1, this ratio after the lapse of three half lives of R will be : Options 1.  3 : 2 2.  1 : 3 3.  1 : 1 4.  2 : 1

Dear student
let t1 and t2 are the time after 3 half lives t1/2,R=0.693λR  after 3 half lives  t1=3×0.693λR...1>similarly  =t2=3×0.693λQ....2>now using formula NRNQ=N0R e-λR t1N0Q e-λQ t2=2 e-λR3×0.693λR1 e-λQ3×0.693λQ=21×1hence NRNQ=21Regards

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