Two radioactive substances A and B have decay constants 5(lambda) and lambda At t=0 they have same no - Physics - Nuclei

Question

Two radioactive substances A and B have decay constants
5(lambda) and lambda At t=0 they have same no of nuclei The ratio
of no of nuclei of A to those of B will be (1/e)^2 after a time
interval
1- 4/lambda
2-2/lambda
3-1/2(lambda)
4-1/4(lambda)

Neha Gupta · Accepted Answer

Decay equation is given by:N = N0 e-λtFor nuclei ANA = Noe-5λtfor B NB = Noe-λtwhere N0 is the no of nuclei at t = 0NANB= Noe-5λtNoe-λt1e2 = e-4λte-2 = e-4λtt = 12λ

Two radioactive substances A and B have decay constants 5(lambda) and lambda . At t=0 they have same no. of nuclei.The ratio of no.of nuclei of A to those of B will be (1/e)^2 after a time interval 1- 4/lambda 2-2/lambda 3-1/2(lambda) 4-1/4(lambda)

Two radioactive substances A and B have decay constants 5(lambda) and lambda . At t=0 they have same no. of nuclei.The ratio of no.of nuclei of A to those of B will be (1/e)^2 after a time interval

1- 4/lambda

2-2/lambda

3-1/2(lambda)

4-1/4(lambda)