two resistors of 10 ohm and 15 ohm are connected in series to a battery of 6V. How can the values of current passing through them be compared?

In series combination , current through the resistors remains same while voltage across the resistorsis different.
R = 10+15 = 25 ohm
I = V/R = 6/25 = 0.24 A

  • 15

These resistors are connected in series. And in series the current would be equally divided among each resistor. So,

For the resistor of 10 ohm the current wud be V=IR

I=V/R

I=6/10

I= 0.6 A

Now the current for the second resistor would be,

V=IR

I=V/R

I=6/15

I=0.4 A

So the current 0.6 A is larger than 0.4 A.

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  • 35

Rs=R1+R2.=10 +15=25 ohm.

V=R x I.

I=V/R=6/25.=0.24A.

Through both resistors 0.24 A current will flow.

there is no comparison .

Hope it helps you.

  • 5
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