Two ships which are on the same side and at a distance of 40 m apart observes the top of a light house at the angles of elevation 30° and 60°. Find the height of the light house and the distance of the ships from the light house. Share with your friends Share 0 Varun.Rawat answered this Let AB be the lighthouse of height h.Let C and D be the position of the 2 ships, such that CD = 40 m.Let ∠ACB = 60° and ∠ADB = 30°In ∆ABC, tan 60° = ABBC⇒3 = hBC⇒BC = h3 ....1In ∆ABD,tan 30° = ABBD⇒13 = hBC + CD⇒3h = BC + 40⇒3h = h3 + 40⇒3h - h3 = 40⇒3h - h3 = 40⇒2h = 403⇒h = 203Now, from 1, we getBC = 2033 = 20So, height of lighthouse = 203 mDistance of first ship from lighthouse = BC = 20 mDistance of second ship from lighthouse = BD = 20+40 = 60 m 1 View Full Answer Ankit Pandey answered this what the heck is it' -1