Login

 Two solids X and Y float on water, floats with half of its volume submerged while Y floats with one-third of its volume out of water. The densities of X and Y arein the ratio of:

(a)4:3

(B)3:4

(C)3:4

(D)1:3

(My answer is coming 4:3 but in answer key it is given 3:4 )

Hi,
prakharmilitary has given absolutely correct answer. So, you can refer to it.
 
Here we use the concept of Archimedes Principle which sates that force of buoyancy on an object is equal to the weight of the fluid displaced by the object. Here fluid is water.
 
Also, when a body floats on a fluid, the magnitude of the buoyant force on the body is equal to the magnitude of the gravitational force on the body (weight of the body).
Therefore,

 

Hope this helps,
@prakharmilitary. Good answer and well explained. You get a thumb up. Keep posting!!
Cheers!!

  • 26
View Full Answer

Here

buyoancy force=weight of the object

pgv/2=p2gv

pg2v/3=p1gv

density of the water/density of the solid x=volume of solid/volume of solid in water

therefore density of solid*volume of solid=density of water * volume of solid in water

now for the solid y

density of the water/density of the solid y=volume  of solid/volume of solid in water

this gives 

density* volume of solid in water=density of solid* volume of solid

Now dividing we get

volume of solid in water for solid x/volume of solid in water for solid= density of solid x/density of solid y

1/2/2/3=density of solid x/density of solid y

3/4=density of solid x/density of solid y

therefore the density of x and are in the ratio 3:4. It is so because we will divide x by y because we have to find the ratio of x to y and if we would have to find the ratio of y to x then it would be 4:3. Because then we would divide y by x

 

therfore answer = 3:4. (proved)

  • 12

Here p2 is the density of solid x and p1 is the density of solid y

  • 1
What are you looking for?