Two sources A and B are sounding notes of frequency 660Hz. A listener moves from A to B with a constant velocity u. If the speed of sound is 330m/s, what must be the value of u so that hears 8 beats per second? Ans is 2m/s

Dear Student, 
Please find below the solution to the asked query: 
Apparent frequency of sound heard by the observer from source A:n1 = v-vov+vsn=v-uv+vsnApparent frequency of sound heard by the observer from source B:n2 = v+vov-vsn=v+uv-vsnNo. of beats = 8n2-n1=8v+uv-vsn -v-uv+vsn = 8330+u330-0660 -330-u330+0660 = 82×660u330=84u=8u=2 m/s
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