Two unbiased dice are thrown. Find the probability that neither a

doublet nor a total of 10 will appear.

let A: a doublet appear

  B: total of 10  be the 2 events

Now  P(A)=6/36= 1/6...  [ (1,1) (2,2)........(6,6)]

........P(B)= 3/36 = 1/12.....{(4,6) (6,4) (5,5) }

  P (A INTER> B) = 1/36  .... (5,5)

therefore P(AU B) = P(A) +P(B)-P(A INTERS. B)

= 1/6 +1/12 -1/36 = 8/36 = 2/9

therefore req. probability = 1 - P(A U B ) = 1 - 2/9 = 7/9

hope u get it.......

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Wrong answer
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Wrong answer
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Siddharth and Anand, it is the right answer.....
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Can it be done using PnC
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