Two waves are represented as: y1=10-2 sin 50t+x50+0 4y2=10-2cos 50t+x50 What is the phase difference between the two waves - Physics -

Question

Two waves are represented as:
y 1 = 10 - 2   sin   50 t + x 50 + 0 4 y 2 = 10 - 2 cos
  50 t + x 50
What is the phase difference between the two waves?

Vijay Shankar Yadav · Accepted Answer

Dear Student,
Waves are y1=10-2sin(50t+x/50+
4)y2=10-2cos(50t+x/50)or y2=10-2sin(π2+50t+x/50)by comparing we are seeing phase difference =900-
43 14×1800=67 070
Regards

Two waves are represented as: y 1 = 10 - 2 sin 50 t + x 50 + 0 . 4 y 2 = 10 - 2 cos 50 t + x 50 What is the phase difference between the two waves?

Two waves are represented as:
$y_{1} = 10^{- 2} \sin [50 t + \frac{x}{50 + 0.4}] y_{2} = 10^{- 2} \cos [50 t + \frac{x}{50}]$
What is the phase difference between the two waves?