Two wires are of the same material have masses in the ratio 3:4. What is the ratio of their extensions under the same load , if their lengths are in the ratio 9:10? Share with your friends Share 3 Rajnish Kumar answered this Dear Student using Hooke's law Y=FLA∆L∆L=FLAY=FLmLρY =FLmLρY=FL2ρmY =FρY×L2m=cL2m (where c=FρY= constant)∆L1∆L2=L12m1L22m2=L1L22×m2m1=9102×43=81100×43=2725 Regards 19 View Full Answer