Two wires are of the same material have masses in the ratio 3:4. What is the ratio of their extensions under the same load , if their lengths are in the ratio 9:10?

Dear Student
using Hooke's law 
Y=FLALL=FLAY=FLmLρY  =FLmLρY=FL2ρmY  =FρY×L2m=cL2m  (where c=FρY= constant)L1L2=L12m1L22m2=L1L22×m2m1=9102×43=81100×43=2725
Regards
 

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