Two wires of the same material are stretched with the same force.Their diameters are 1.2 mm and 1.6 mm, while their lengths are 90 cm and 60 cm respectively.If the frequency of vibrations of first is 256 hz,find that of the other.

Two wires of the same material are stretched with the same force.Their diameters are 1.2 mm and 1.6 mm, while their lengths are 90 cm and 60 cm respectively.If the frequency of vibrations of first is 256 hz,find that of the other.
The fundamental frequency of stretched string is given by
f=12LFμ
Here μ is mass per unit length means linear mass density

According to question,
f1f2=L2L1μ2μ2256f2=6090πρr22πρr22=6090r2r1=6×1.69×1.2or, f2=2566×1.6×9×1.2=288 Hz
Hence required frequency is 288 Hz
 

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