Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3 as efficiently as he actually did, the work would have been completed in 3 days. Find the time taken by A alone to complete the work?
Let A completes the work in x days
and B completes the work in y days
So, Work of A in 1 day
and work of B in 1 day
and so work of A and B in 1 day
According to question,
If A worked twice as efficiently as he actually did and B worked as efficiently as he actually did, the work would have been completed in 3 days.
So, A will complete the work in days
and B will complete the work in 3y days.
Multiplying (1) by 2 and then subtracting (2) from it–
∴ From (1), we get –
Hence, A takes days i.e., days to complete the work.