Units and measurements plz solve?? Share with your friends Share 0 Vipra Mishra answered this Dear Student Mean value of quantity measured, x=1.29+1.33+1.34+1.35+1.32+1.36+1.30+1.338x =1.3275 = 1.33 ( round off to two plces of decimals)Absolute errors in measurement are∆x1=1.33 - 1.29 = 0.04∆x2=1.33 - 1.33 = 0.00∆x3=1.33 - 1.34 =- 0.01∆x4=1.33 - 1.35= -0.02∆x5=1.33 - 1.32 = 0.01∆x6=1.33 - 1.36 = -0.03∆x7=1.33 - 1.30 = 0.03∆x8=1.33 - 1.33 = 0.00Mean absolute error ∆x¯ = ∑i=li=n△xinMean absolute error ∆x¯ = 0.04+ 0.00+ 0.01+ 0.02+ 0.01+ 0.03+ 0.03+ 0.008∆x¯ =0.148 = 0.0175 = 0.02Relative error =±∆x¯x =±0.021.33 = ±0.015 =±0.02Percentage error =±0.015 x 100 = 1.5% Regards 0 View Full Answer Arjun Baiju Supriya answered this I will try and update 0