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how to find limit of x----9

x3/2-27/x-9

limx→9x3/2-27x-9In this function ,if we put 9, it gets changed into 00form.To remove the 00form, we will differentiate numerator and denominator individually, untill 00 formis removed.Hence limx→9x3/2-27x-9 =limx→9ddx(x3/2-27)ddx(x-9)=limx→932x1/21, thus 00 form is removed, put 9 to get the limit.=limx→932(9)1/21=92 hence limx→9x3/2-27x-9 =92 Ans

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plz enter the ques. properly !

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its correct

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limit as x ------ 9 (x3/2 - 27)/(x - 9)

= limit as x -------9 (x3/2 - 93/2)/(x - 9)

= 3/2(9)3/2 - 1 [As limit as x ------a (xn - an)/(x - a) = nan - 1)

= 3/2(9)1/2

= 3/2*3

= 9/2.

So, limit as x ------ 9 (x3/2 - 27)/(x - 9) = 9/2

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