urgent angular velocity of an electron occupying second orbit of Li2+ ion I want answer involving h,pi,k etc as i got the answer for the other method ,ie, mv2/r = kZe2/r Share with your friends Share 6 Vaibhav T. answered this Dear Student, According to Bohr model,mv2r=KZe2r2or, r=KZe2mv2 ......... (1)and also we know that angular momentum of the orbiting electron is quantized, i.e., mvr=nh2π .......... (2)from (1) and (2),nh2πmv=KZe2mv2v=2πKZe2nh ....... (2)Also, v=rωwhere, ω=angular velocityω=vrω=2πKZe2nhKZe2mv2ω=2πKZe2nh×mv2KZe2or, ω=2πKZe2nh×m2πKZe2nh2KZe2ω=2πKZe2nh×m×4π2K2Z2e4n2h2×KZe2ω=m×8π3K2Z2e4n3h3For Li2+, n=2 and Z=3Therefore, ω=9π3mK2e4h3 22 View Full Answer
