(urgently) 17) [ (2x + 1) /7x â 1 ] 5 , [ (x + 7) / - Maths - Linear Inequalities

Question

(urgently)
17) [ (2x + 1) /7x â€“ 1 ] >5 , [ (x +
7) / x â€“ 8 ] > 2
today i need answer

Gursheen kaur. · Accepted Answer

$\frac{2 x + 1}{7 x - 1} > 5 \frac{2 x + 1}{7 x - 1} - 5 > 0 \frac{2 x + 1 - 35 x + 5}{7 x - 1} > 0 \frac{- 33 x + 6}{7 x - 1} > 0$

clearly, 7x-1 is not equal to 0.

therefore, two possibilities exist.

$i) 7 x - 1 > 0 \Rightarrow x > \frac{1}{7} t h e r e f o r e, \frac{- 33 x + 6}{7 x - 1} > 0 \Rightarrow - 33 x + 6 > 0 \Rightarrow - 33 x > - 6 \Rightarrow x > \frac{6}{33} \Rightarrow x > \frac{2}{11} \Rightarrow x > \frac{1}{7} & x > \frac{2}{11} \Rightarrow x > \frac{1}{7} i i) 7 x - 1 < 0 x < \frac{1}{7} t h e r e f o r e, \frac{- 33 x + 6}{7 x - 1} > 0 \Rightarrow - 33 x + 6 < 0 \Rightarrow x < \frac{2}{11} & x < \frac{1}{7} \Rightarrow x < \frac{2}{11} o n c o m b i n i n g (i) a n d (i i) r e s u l t s, t h e s o l u t i o n o f g i v e n i n e q u a t i o n i s \frac{1}{7} < x < \frac{2}{11}$

(urgently) 17) [ (2x + 1) /7x – 1 ] >5 , [ (x + 7) / x – 8 ] > 2 today i need answer

(urgently)

17) [ (2x + 1) /7x – 1 ] >5 , [ (x + 7) / x – 8 ] > 2

today i need answer