URGENTThe ionic strength of a solution containing 0.1 mol/kg of NaCl and 0.2 mol/kg of ZnSO₄ is : solve it ..

• A)

  0.3

• B)

  0.6

C)0.4

• D)

  0.9

....

Since, we know that ionic strength is calculated as :
$$\begin{gathered} I=1/2\sum {z_i}^2{m}_i \\ Where, Z = valency factor and m= concentration \end{gathered}$$
In the given solution mixture, the concentrations are :
[Na⁺] =0.1m
[Cl^-] = 0.1m
[Zn⁺²] = 0.2m
[SO₄^-2] =0.2m
So, I = 1/2{0.1 x1^​2 + 0.1 x1² + 0.2x2² + 0.2 x 2²] = 1/2 [0.1+0.1+0.8+0.8]
Hence, I = 1.8/2 = 0.9
Hence, the correct answer is d). 0.9