# Use Kirchhoff's rules to determine the potential difference between points A and D when no current flows in the arm BE of the network shown .

Dear student,

Applying kirchoffs law in circuit AFEBA,
If current I follows through circuit,
$2I+3I+{R}_{1}{I}_{1}=6-1-1\phantom{\rule{0ex}{0ex}}5I+{R}_{1}{I}_{1}=4$
As no current flows through arm BE, I1=0.
I=0.8 A.
Current through resistance R is 0.8A
The potential difference across AD is 2V.

Regards.

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