A tailor has a piece of canvas whose area is 552 msquare.He uses it to make a conical tent with base radius 7m. Assuming that all stitching margins and wastage is 2msquare. Find the volume of the tent that can be made with it

Area of the total piece of cloth = 552 m‚Äč2
area of cloth wasted = 2 m2
area left for making tent = 550 m2
radius of base, r = 7 m
Let height = h
Let slant height = l
CSA = 550 πrl = 550227×7×l = 550l = 25 mnow, h = l2 - h2      h = 625 - 49 = 576 = 24 mvolume of tent = 13πr2h = 13×227×49×24 = 1232 m3


 

  • 10

total curved surface area = 522m2

wastage and margins = 2 m2

Actual area = (522 - 2) m2 = 550m2

C.S.A = xrl = 550m2

l = 550 x 7/7 x 22

l = 25m

h2 = l2 - r2

h2 = 252 - 72 m

h = 24m

volume = 1/3xr2h

= 1/3 x 22/7 x 72 x 24 m3

= 1232m3

  • 8
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