using elementary transformation, find the inverse, if it exists : [1 -1] [2 3] Share with your friends Share 0 Ajanta Trivedi answered this let the given matrix be A=1-123 since A = IA 1-123=1001A applying R2→R2-2R1 1-105=10-21A 1-101=10-2515A applying R2→R2/51001=3515-2515A applying R1→R1+R2 since I=A-1Atherefore A-1=3515-2515 hope this helps you 1 View Full Answer