using elementary transformation, find the inverse, if it exists :

[1 -1]

[2 3]

let the given matrix be A=1-123
since A = IA
1-123=1001A applying R2R2-2R1

1-105=10-21A 

1-101=10-2515A    applying R2R2/51001=3515-2515A    applying R1R1+R2
since I=A-1Atherefore A-1=3515-2515

hope this helps you

 

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