Using factor theorem, show that x-y, y-z, z-x are the factors of x2(y-z)+y2(z-x)+z2(x-y)
Solution :
We know Factor theorem " When x-c is a factor of the polynomial then f(c)=0 . "
So
We have polynomial = x2( y - z ) + y2(z - x ) + z2( x - y )
So according to factor theorem if ( x - y ) is factor of our polynomial so it gives it value zero at x = y
We substitute x = y , And get
= y2( y - z ) + y2(z - y) + z2( y - y )
= y3 - y2z + y2z - y3 + 0
= 0
So ( x - y ) is a factor of our polynomial.
Now check for ( y - z ) is a factor of our polynomial or not
So we substitute y = z , And get
= x2( z - z ) + z2(z - x ) + z2( x - z )
= 0 + z3 - z2x + z2x - z3
= 0
So ( y - z ) is a factor of our polynomial.
Now check for ( z - x ) is a factor of our polynomial or not
So we substitute z = x , And get
= x2( y - x ) + y2(x - x ) + x2( x - y )
= x2y - x3 + 0 + x3 - x2y
= 0
So ( z - x ) is a factor of our polynomial.
We know Factor theorem " When x-c is a factor of the polynomial then f(c)=0 . "
So
We have polynomial = x2( y - z ) + y2(z - x ) + z2( x - y )
So according to factor theorem if ( x - y ) is factor of our polynomial so it gives it value zero at x = y
We substitute x = y , And get
= y2( y - z ) + y2(z - y) + z2( y - y )
= y3 - y2z + y2z - y3 + 0
= 0
So ( x - y ) is a factor of our polynomial.
Now check for ( y - z ) is a factor of our polynomial or not
So we substitute y = z , And get
= x2( z - z ) + z2(z - x ) + z2( x - z )
= 0 + z3 - z2x + z2x - z3
= 0
So ( y - z ) is a factor of our polynomial.
Now check for ( z - x ) is a factor of our polynomial or not
So we substitute z = x , And get
= x2( y - x ) + y2(x - x ) + x2( x - y )
= x2y - x3 + 0 + x3 - x2y
= 0
So ( z - x ) is a factor of our polynomial.