Using integration find area of region bounded by following curve:y= mod(x+1) +1x= -2x = 3y = 0 Share with your friends Share 4 Manbar Singh answered this We have,y = 1 + x + 1 = 1 + x + 1 = x + 2, x ≥ -11 - x + 1 = -x, x < -1The equation of given curves are:-y = x + 2, x ≥ -1 ...............1y = -x, x < -1 ...............2x = -2 ...............3x = 3 ..............4y = 0 .................5Now, equation 1, represents a straight line that intersects x-axis at -2, 0 and y-axis at 0, 2Equation 2, represents a straight line passing through 0, 0 and making an angle of 135° with positive direction of x-axis.Equation 3, represents a straight line parallel to y-axis intersecting x-axis at -2, 0.Equation 4, represents a straight line parallel to y-axis intersecting x-axis at 3, 0Equation 5, represent x-axis. GRAPH : Required area = ∫-2-1 -x dx + ∫-13 x+2 dx=- ∫-2-1 x dx + ∫-13 x+2 dx=-12x2-2-1 + x22 + 2x-13=-121-4 + 92+6-12-2=32+212+32=32+12=272 square units 6 View Full Answer
.png)