using integration find the area of the region bounded by the line x-y+2=0, the curve x=y^1/2 and y axis.

The diagram will look as shown below. We need to find area of the shaded (green) region

Required area (A)=0a(x+2)-x2dxFirst we need to get 'a'This represent the point of intersection of the two curves, so we equate the two functions:x+2=x2x2-x-2=0x2-2x+x-2=0(x-2)(x+1)=0since x>0, we reject the solution x=-1Hence, a=2So:A=02(x+2)-x2dx=x22+2x-x3302=2+4-83=103

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even i wanted the answer to this qn
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@ Hayat & @Gopika Anil
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the first equation x-y +2 =0 is an equation of line.
u can plot it by taking x=0 then y=2 & if y=0 then x= -2 so points will be (0,2) & (-2,0) &
the other curve is twisted
actually if you square on both sides you will get y =x^2which is a parabola along the Y-axis ( Upward Parabola)
plot the curves to get the bounded area!
while solving the
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