using matrices, solve the following system of equations 3x+4y+7z=4: 2x-y+3z=-3: x+2y-3z=8

The system of equestion can be written in the form AX=B,Where A= 3 4 7 X= x B= 4 2 -1 3 y -3 1 2 -3 z 8Then find mode A.Find adj (A).A^-1 = 1/mode A x adj(A)Then find X=A^-1B