using property of stp prove that [a bar+b bar b bar+c bar c bar+a bar]=2[a bar b bar c bar] Share with your friends Share 0 Ishwarmani answered this Dear Student, Please find below the solution to the asked query: LHS=a→+b→b→+c→c→+a→=a→+b→·b→+c→×c→+a→=a→+b→·b→×c→+a→+c→×c→+a→=a→+b→·b→×c→+b→×a→+c→×c→+c→×a→=a→+b→·b→×c→+b→×a→+0→+c→×a→=a→+b→·b→×c→+b→×a→+c→×a→=a→·b→×c→+b→×a→+c→×a→+b→·b→×c→+b→×a→+c→×a→=a→·b→×c→+a→·b→×a→+a→·c→×a→+b→·b→×c→+b→·b→×a→+b→·c→×a→=a→·b→×c→+a→·b→×a→+a→·c→×a→+b→·b→×c→+b→·b→×a→+b→·c→×a→=a→b→c→+0→+0→+0→+0→+b→c→a→=a→b→c→+a→b→c→=2a→b→c→=RHS Regards 0 View Full Answer