USING PYTHGORAS THEOREM.
Q.17. In ABC, AB = AC = x, BC = 10 cm and the area of ABC is 60 c m 2 . Find x.


Let ADBC.In ADB and ADCADB = ADC  90° each       AB = AC         Given       AD = AD         CommonADB ~ ADC  RHSBD = DC  CPCTSo, BD = DC = 5 cmNow, area of ABC = 60 cm212×BC×AD = 6012×10×AD=60AD = 12 cmIn ADC,AC2 = AD2 + DC2   Pythagoras theoremx2 = 122 + 52x2 = 144 + 25x2 = 169x = 13

 

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