using second law of motion derive the relation between force and acceleration . a bullet of 10g strike a sand bag at a speed of 1000m/s and gets embeded after travelling 5 cm .calculate
(1)the resistive force exerted by sand on bullet
(2)the time taken by the bullet to come to rest
we have
v2 - u2 = 2as
or
acceleration
a = (v2 - u2) / 2s
here,
u = 1000m/s
v = 0
s = 5cm = 0.05m
so,
a = (0 - 10002) / (2x0.05)
thus,
a = -10000000 m/s2
and the retarding force will be
F = ma
here,
m = 10g = 0.01kg
so,
F = 0.01 x 10000000
thus,
F = 100000N
..
time taken will be
t = (v - u) / a
or
t = (0 - 1000) / -10000000
thus,
t = 0.0001s