Using the distance formula show that The points (4,3) (5,1) and (1,9) are collinear

Hi Ahamed dear, distance AB = √{(-1)^2 + (2)^2} = √5
Distance BC = √{(4)^2 + (-8)^2} = ​√80 = 4√​5
Distance AC = √​{3^2 +(-6)^2} = √45 = 3√5
It is vivid clear that BC = BA + AC
A, B and C are collinear with A lies in between B and C
 

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