Using the law of transversals, please help me find Angle BAC in the picture below: Share with your friends Share 0 Vijay Kumar Gupta answered this Contruct a line PQ through point C parallel to DE.Note that two lines parallel to the same third line are also parallelto each other.So we have PQ is also parallel to AB. The figure is shown below: Note that DE∥CQ and DC is transversal CQ is part of straight line PQ and PQ∥DEThis implies that ∠CDE and ∠DCQ are interior angles on the same side of transversal, so their sum must be 180°. ∠CDE +∠DCQ=180° 111° +∠DCQ=180° ∠DCQ=180°-111° ∠DCQ=69°Now we have AB∥CQ and BC is transversal.So ∠ABC and ∠BCQ are alternate interior angles, so they must be equal. ∠BCQ=∠ABCBut ∠BCQ=∠BCD+∠DCQ which gives, ∠BCD+∠DCQ=120° ∠BCD+69°=120° ∠BCD=120°-69° ∠BCD=51° 1 View Full Answer Aditi answered this Not angle BAC, please help me find angle BCD? 0