VALUE BASED QUESTION:-
A
HIGHWAY LEADS TO THE FOOT OF 300m HIGH TOWER. AN OBSERVATORY IS SET AT THE TOP OF THE TOWER. IT SEES A CAR MOVING TOWARDS IT AT AN ANGLE OF DEPRESSION OF 30 DEGREE. AFTER 15 SECONDS ANGLE OF DEPRESSION BECOMES 60 DEGREE.

A) FIND THE DISTANCE TRAVELLED BY THE CAR DURING THIS TIME.
B) HOW THIS OBSERVATORY IS HELPFUL TO REGULATE THE TRAFFIC ON THE HIGHWAY.



Let AB be the tower. Now, AB = 300 mLet D be the first poisition and C be the second position of the car.Let ADB = 30°; ACB = 60°In ABC,tan 60° = ABBC3 = 300BCBC = 3003 = 30033 = 1003 mIn ABD,tan 30° = ABBD13 = 300BC + CDBC + CD = 30031003 + CD = 3003CD = 2003 mSo, distance between 2 positions = 2003 = 200 × 1.73 = 346 mSo, distance travelled in 15 sec = 346 m

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