Vapour pressure of pure water is 760mm at 25°C. The vapour pressure of solution containing 1m solution of glucose will be ? Share with your friends Share 13 Geetha answered this According to lowring of vapour pressurep0 - pp0 = W2M2 × M1W1 ---- 1Where W2 -weight of the soluteW1 - Weight of the solventM2 - molecular mass of the soluteM1 - molecular mass of the solvent water - 18p- vapour pressure of the solutionp0 - vapour pressure of the pure solvent - 760 We know molality = Numer of moles of soluteKg of the solvent = W2M2W1 in g × 103 So in the above equation 1p0 - pp0 = m× M1 ---- 2760 - p760 = 1 × 10-3 × 18p = 746.32 mm 46 View Full Answer
