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verify rolles theorem for the function f(x)=sinx-sin2x in[0,pie]

Rolles therom is applicable in this function..
As,
1.) It's continuous
2.) It's differentiable
3.) f(0) = f(π)
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qw
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sir please explain how it is continuos and differentiable and find the value of c
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F(x) = sinx - sin2x on(0,pie) by rolls theoram
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We have, f(x) = sin x - sin 2x in [0,π]
We know that all trigonometric functions are continuous and differentiable in their domain, given function is also continuous and differentiable
f(0) = sin0 -sin2*0 = 0    & f(π) = sinπ - sin2π = 0
so, f(0) = f(π)
Hence, there exists atleast one c ∈ (0,π) such that , 






So, all the conditions of rolle's theorm is Verified!!
CHEERS!!

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