verify that y2 =4a(x+a) is a solution of the differential equation y{1-(dy/dx)2}=2xdy/dx

Given, y2=4ax+aDifferentiating both side w.r.t.x, we get,ddxy2=ddx4ax+a2ydydx=ddx4ax+ddx4a22ydydx=4a+0dydx=2ayNow,L.H.S.=y1-dydx2=y1-2ay2           =yy2-4a2y2           =y2-4a2y           =4ax+a-4a24ax+a           =4ax4ax+a           =2x2a4ax+a           =2x2ay           =2xdydx           =R.H.S.Hence Proved.

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