Verify the following:
  • If abc is a three-digit number, then ( abc + cab + bca ) will be a multiple of 3 and 37.

Dear Student,


any 3 digit number abc can be written as 100a+10b+cHence we got abc+cab+bca100a+10b+c+100c+10a+b+100b+10c+a111a+111b+111c111×a+b+cnow factors of 111 are 3×37Hence abc+cab+bca=3×37×a+b+ctherefore the number abc+cab+bca is divisible by 3 and 37

Regards,

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