volume at NTP of oxygen required to completely burn 1 Kg of coal (100% carbon )
solve it ?
Reaction for complete combustion is as follows:
C + O2 → CO2
1 mole of carbon or 12 g of carbon require 1 mole of Oxygen or 32 g of Oxygen
1000 g or 1 kg of Carbon will react with
= 2666.67 g of Oxygen
1 mole of oxygen or 32 g of Oxygen at NTP occupy 24.07 L volume
So 2666.67 g of Oxygen will occupy 24.07 X 2666.67 / 32
= 2005.84 L volume
So volume of Oxygen require will be 2005.84 L for complete burning of 1 kg of Coal having 100 % carbon.
C + O2 → CO2
1 mole of carbon or 12 g of carbon require 1 mole of Oxygen or 32 g of Oxygen
1000 g or 1 kg of Carbon will react with
= 2666.67 g of Oxygen
1 mole of oxygen or 32 g of Oxygen at NTP occupy 24.07 L volume
So 2666.67 g of Oxygen will occupy 24.07 X 2666.67 / 32
= 2005.84 L volume
So volume of Oxygen require will be 2005.84 L for complete burning of 1 kg of Coal having 100 % carbon.