Volume at NTP of oxygen required to completely burn 1 kg of coal(100% carbon) is...??

Equation: C + O2 ? CO2 1mol C will react with 1 mol O2 Mass ratio 12:32 1kg coal will require 1*32/12 = 2.667kg = 2,667 g O2 Molar mass O2 = 32g/mol 2,667g = 2667/32 = 83.34mol Ar NTP 1 mol = 24L 83.34 mol = 83.34*24 = 2000L You ask about NTP = my understanding is that at NTP 1 mol gas = 24L But at STP , 1 mol gas = 22.4L At STP , 83.34mol = 83.34*22.4 = 1,867L OR 1.86*10^3 L Volume of O2 required art STP = 1.86*10^3 L
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