# water flowing at the rate of 2.52km /hr through a cylindrical pipe into a cylindrical tank the radius of whose base is 40 cm if the increase in the level of water in the tank in half an hour is 3.15 m find the internal diameter of the pipe

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Internal Diameter of cylindrical pipe = 4cm.
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tell me also
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fully solved

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speed of water=2.52km/hr=2520m/hr
length = 2520m/hr
let the radius of pipe = r
and radius of tank =40 cm=4/10m
length of tank in half hour = 3.15m
length of tank in an hour = 2*3.15m =6.3m
now,
volume of pipe = volume of tank
pie *r ^2 * 2520= Pie *4/10*4/10*6.3
r^2 =1/2500 m
r= 1/50 m
diameter = 2/50 m = 200/50 cm = 4 cm
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u r right
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tum sabka answer glat hai pagalo
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thank you

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Plz try twice or thrice

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Plz try twice or thrice

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4 cm
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4cm
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Here is a better answer. FULLY EXPLAINED 😊😊

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I hope this is clear

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this will help u
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4cm
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good job abhi!!!!

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Height of tank in half an hour=3.15m=H
Water flow in 1 hour =2520 m
Water flow in half an Hour=1260m which can taken as height of pipe
h=1260m
thus

pie *r^2* h=pie *R^2* H
r^2 *h=R^2*H
r^2=R^2*H/h

r^2=0.4*0.4*3.15/1260
r^2  =0.04m
r=2cm
d=4cm

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thanks !
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ans 4cm
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speed of water=2.52km/hr=2520m/hr length = 2520m/hr let the radius of pipe = r and radius of tank =40 cm=4/10m length of tank in half hour = 3.15m length of tank in an hour = 2*3.15m =6.3m now, volume of pipe = volume of tank pie *r ^2 * 2520= Pie *4/10*4/10*6.3 r^2 =1/2500 m r= 1/50 m diameter = 2/50 m = 200/50 cm = 4 cm
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Thanks
Regards
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