Water flows through the tube shown Area of cross-section of wide and narrow part are 5 cm2 and 2 - Physics - Electromagnetic Induction

Question

Water flows through the tube shown Area of cross-section of wide
and narrow part are 5 cm2 and 2 cm2 The rate
of flow is 500 cm /sec Find difference in mercury level of U-tube
:-anw
1 90 cm how it work out

Jyoti Pant · Accepted Answer

Here,v1=5005=100 cm/sand v2=5002=250 cm/sNow, using Bernoulii's equationp1+12ρ v12=p2+12ρv22or p1-p2=12ρv22-12ρ v12Thus, in the given case pressure difference=12×1(625×102-100×102)Now,h×13
6×980=50×625or h=1 97 cm

Water flows through the tube shown. Area of cross-section of wide and narrow part are 5 cm2 and 2 cm2. The rate of flow is 500 cm /sec. Find difference in mercury level of U-tube :-anw 1.90 cm how it work out

Water flows through the tube shown. Area of cross-section of wide and narrow part are 5 cm² and 2 cm². The rate of flow is 500 cm /sec. Find difference in mercury level of U-tube :-anw 1.90 cm how it work out