water is flowing at the rate of 15km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50m long and 44m wide . find the time in which the level of water in the tank will rise by 21 cm

 For the pipe...

Speed = 15 km/hr = 1500000 cm/hr = 1500000/60 cm/min = 2500 cm/ min

radius = 7cm

Volume of water that flows through the pipe per minute...

=> pi * r2 * h = 49 * 2500 * pi = 122500 pi cm2

For the tank.....

volume = 4400 * 5000 * 21 cm2 = 462000000 cm2

Now, Time = distance/speed

=4620000 * 7/ 122500 * 22 = 1200 min = 20 hrs

 

 

 

 

 

cm2

Now, Time = distance/speed

= 4620000 * 7/ 122500 * 22 = 1200 min = 20 hrs

  • -21

 Let the level of water in the pond rises by 21 cm in t hours.

Speed of water = 15 km/hr

Volume of water flowing out of the pipe in 1 hour

= π r 2 h

= 231 m3

∴ Volume of water flowing out of the pipe in t hours = 231 t m3.

Volume of water in the cuboidal pond

= 462 m3

Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond

∴ 231 t = 462

Thus, the water in the pond rise by 21 cm in 2 hours.

 

  • 277
I don't know
  • -18
i need expert answer coz ans uinunderstandable and both answers are dif
 
  • -21
Pipe is equal to rectangle ha ha ha
  • -25
the answer can never be 20 hrs , r u brainless akshita :-[
  • -18
Let the level of water in the pond rises by 21 cm in t hours. Speed of water = 15 km/hr Volume of water flowing out of the pipe in 1 hour = π r2h = 231 m3 ∴ Volume of water flowing out of the pipe in t hours = 231 t m3. Volume of water in the cuboidal pond = 462 m3 Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond ∴ 231 t = 462 Thus, the water in the pond rise by 21 cm in 2 hours.
  • -9
its saying the volume not the shape
 
  • -22
wrong
 
  • -18
Answer any one tough questions

  • -22
Plzz answer the 5th question

  • -18

Let the level of water in the pond rises by 21 cm in t hours.

Speed of water = 15 km/hr

Diameter of the pipe = 14/100 m

Radius of the pipe (r) = 7/100 m

Volume of water flowing out of the pipe in 1 hour

= π r 2 h

= (22/7) x (7/100) x (7/100) x 15000

= 231 m3

Volume of water flowing out of the pipe in t hours = 231 t m3.

Volume of water in the cuboidal pond

= 50 x 44 x (21/100)

= 462 m3 

Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond

So, 231 t = 462

t = 2

Thus, the required time is 2 hours.

  • 76
I don't know
  • -18
Let the level of water in the pond rises by 21 cm in t hours. Speed of water = 15 km/hr Volume of water flowing out of the pipe in 1 hour = π r 2 h = 231 m3 ∴ Volume of water flowing out of the pipe in t hours = 231 t m3. Volume of water in the cuboidal pond = 462 m3 Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond ∴ 231 t = 462 Thus, the water in the pond rise by 21 cm in 2 hours. . . . Ayush Patel ....
  • -2
Given diameter of cylinder = 14 cm
Therefore radius of cylinder, r = 7 cm
Volume of cylinder = πr2h cubic units
Volume of water flowing through the cylindrical pipe in 1 hour at the rate of 15km/hr
= (22/7) x (7/100) x (7/100) x 15000 = 231 cu m
We know that volume of cuboid = lbh cubic units
Therefore volume of water in the tank = 54 x 44 x (21/100) = 462 cu m
Time taken = (462/231) = 2 hours
  • 19
She is brainless the answer is 2hours
  • -3
In cylinder,
r=7cm=0.7m
l=15km
 =15000m

In tank,
l=50m
b=44m
h=0.21m

Vol.of water in tank=lbh
                               =50*44*0.21
                               =462m³

Height of cylindrical pipe=Vol. / πr²
                                      =462/(0.07)²(22/7)
                                      =462/0.0154
                                      =30000m

Time = 30000/15000
         = 2 hours
  • 7
Easier method

  • 8
 Pipe, H= 15km/hr= 15000m/hr
           r= 7/100 m
Let time taken be T.....
volume= ​πr2​​h= 22/7 x 7/100 x 7/100 x 15000 x T
Cuboidal Tank- L=50m
                         B= 44m
                          H= 21/100
Volume= LBH= 50 x 44 x 21/100
Volume of pipe x time = volume of cuboidal tank
22/7 x 7/100 x 7/100 x 15000 x T= 50 x 44 x 21/100
T = 44/22
=2 hours
  • 20
Hope it helps you

  • 34
its written above so u all can see
 
  • -11
2 hours
  • -7
The answer is 2 hours Hope it helps Cheeeeers
  • -3
2 hours Hope it helps Cheeers
  • -4
yes 2 hours is the right answer
  • -1
Plz like

  • 1
Plz share

  • 6
2 hours
  • -3
the answer will be 2 hours
  • -3
2 hrs would be the answer
  • -2
2 hrs
 
  • -2
In cylinder, r=7cm=0.7m l=15km  =15000m In tank, l=50m b=44m h=0.21m Vol.of water in tank=lbh                                =50*44*0.21                                =462m³ Height of cylindrical pipe=Vol. / πr²                                       =462/(0.07)²(22/7)                                       =462/0.0154                                       =30000m Time = 30000/15000          = 2 hours
  • 4
answer 
  • 0
answer 
  • 0
answer s
  • 1
????? 10th
  • 0
44 hrs.
  • 0
Please find this answer

  • 0
Let rcm be the radius and h cm be the height of a pipe(cylinder),then r=7cm=7/10m and h=5km=5000m [Distance covered in 1 hr=height of pipe] Now,Volume of water that flows out of the circular pipe in 1hr =
  • 0
Maths
  • 0
Here's is the Answer which you wanted 

Thanks 
Regards 
In cylinder,
r=7cm=0.7m l=15km b=15000m
In tank,
l=50m b=44m h=0.21m
Volume of water in tank= length x breadth x height  =50 x 44 x 0.21  =462m³
Height of cylindrical pipe=Volume / πr²    =462/(0.07)²(22/7)   =462/0.0154    =30000m
Time = 30000/15000 = 2 hours
  • 1
yudha
  • 0
What are you looking for?