water is flowing at the rate of 15km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50m long and 44m wide . find the time in which the level of water in the tank will rise by 21 cm

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Akshita Viswan answered this

For the pipe...

Speed = 15 km/hr = 1500000 cm/hr = 1500000/60 cm/min = 2500 cm/ min

radius = 7cm

Volume of water that flows through the pipe per minute...

=> pi * r² * h = 49 * 2500 * pi = 122500 pi cm²

For the tank.....

volume = 4400 * 5000 * 21 cm² = 462000000 cm²

Now, Time = distance/speed

=4620000 * 7/ 122500 * 22 = 1200 min = 20 hrs

cm²

Now, Time = distance/speed

= 4620000 * 7/ 122500 * 22 = 1200 min = 20 hrs

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Alisha Shah answered this

Let the level of water in the pond rises by 21 cm in t hours.

Speed of water = 15 km/hr

$n n Diameter of pipe n n n = n n n 14 n cm n n n = n \frac{n}{n 14 n} n m n n n n n ∴ n Radius of the pipe,� n n n r n n n = n n n \frac{n}{n 7 n} n m n n n n n n n n n n n n n n n n$

Volume of water flowing out of the pipe in 1 hour

= π r ² h

$n n = n \frac{n}{n 22 n} n n n n � n n n n n n n (n \frac{n}{n 7 n} n m n n^{n) n n n 2 n n} n n n � n n n n 15000 n n n m n n n$

= 231 m³

∴ Volume of water flowing out of the pipe in t hours = 231 t m³.

Volume of water in the cuboidal pond

$n n = n n 50 n n n m n n n n n n � n n n n n n 4 n n n n 4 n n n n n n n m� n n n � n n n n n n \frac{n}{n 21 n} n n n n n n n n n n n n m n �� n n (n ∵ n Volume of cuboid n n n = n n n n n l n b n h n n n n n) n n n$

= 462 m³

Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond

∴ 231 t = 462

$n n \Rightarrow n t n n n = n n n \frac{n}{n 462 n} n n n = n n n 2 n n n n n n n n n n$

Thus, the water in the pond rise by 21 cm in 2 hours.

Prakriti Pai answered this

I don't know

Umar Asif answered this

i need expert answer coz ans uinunderstandable and both answers are dif

Sheikh Ziad answered this

Pipe is equal to rectangle ha ha ha

Tanuj Pokarna answered this

the answer can never be 20 hrs , r u brainless akshita :-[

Tanuj Pokarna answered this

Let the level of water in the pond rises by 21 cm in t hours. Speed of water = 15 km/hr Volume of water flowing out of the pipe in 1 hour = π r2h = 231 m3 ∴ Volume of water flowing out of the pipe in t hours = 231 t m3. Volume of water in the cuboidal pond = 462 m3 Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond ∴ 231 t = 462 Thus, the water in the pond rise by 21 cm in 2 hours.

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Umar Asif answered this

its saying the volume not the shape

Santoshrajha answered this

wrong

Revathi Senthil answered this

Answer any one tough questions

Revathi Senthil answered this

Plzz answer the 5th question

Vijayalakshmi K V answered this

Let the level of water in the pond rises by 21 cm in t hours.

Speed of water = 15 km/hr

Diameter of the pipe = 14/100 m

Radius of the pipe (r) = 7/100 m

Volume of water flowing out of the pipe in 1 hour

= π r ² h

= (22/7) x (7/100) x (7/100) x 15000

= 231 m³

Volume of water flowing out of the pipe in t hours = 231 t m³.

Volume of water in the cuboidal pond

= 50 x 44 x (21/100)

= 462 m³

Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond

So, 231 t = 462

t = 2

Thus, the required time is 2 hours.

Ashfak Ahamed answered this

I don't know

Ayush Patel answered this

Let the level of water in the pond rises by 21 cm in t hours. Speed of water = 15 km/hr Volume of water flowing out of the pipe in 1 hour = π r 2 h = 231 m3 ∴ Volume of water flowing out of the pipe in t hours = 231 t m3. Volume of water in the cuboidal pond = 462 m3 Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond ∴ 231 t = 462 Thus, the water in the pond rise by 21 cm in 2 hours. . . . Ayush Patel ....

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Nafisath Shabnam answered this

Given diameter of cylinder = 14 cm
Therefore radius of cylinder, r = 7 cm
Volume of cylinder = πr2h cubic units
Volume of water flowing through the cylindrical pipe in 1 hour at the rate of 15km/hr
= (22/7) x (7/100) x (7/100) x 15000 = 231 cu m
We know that volume of cuboid = lbh cubic units
Therefore volume of water in the tank = 54 x 44 x (21/100) = 462 cu m
Time taken = (462/231) = 2 hours

Vinay answered this

She is brainless the answer is 2hours

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Venthan answered this

In cylinder,
r=7cm=0.7m
l=15km
=15000m

In tank,
l=50m
b=44m
h=0.21m

Vol.of water in tank=lbh
=50*44*0.21
=462m³

Height of cylindrical pipe=Vol. / πr²
=462/(0.07)²(22/7)
=462/0.0154
=30000m

Time = 30000/15000
= 2 hours

Ria answered this

Easier method

Siddharrth Prem answered this

Pipe, H= 15km/hr= 15000m/hr
r= 7/100 m
Let time taken be T.....
volume= πr²h= 22/7 x 7/100 x 7/100 x 15000 x T
Cuboidal Tank- L=50m
B= 44m
H= 21/100
Volume= LBH= 50 x 44 x 21/100
Volume of pipe x time = volume of cuboidal tank
22/7 x 7/100 x 7/100 x 15000 x T= 50 x 44 x 21/100
T = 44/22
=2 hours

Huyli answered this

Hope it helps you

Rohit Kumar Das answered this

its written above so u all can see

Richa Sharma answered this

2 hours

-7

Sharon answered this

The answer is 2 hours Hope it helps Cheeeeers

-3

Sharon answered this

2 hours Hope it helps Cheeers

-4

Vayun Ekbote answered this

yes 2 hours is the right answer

-1

Randhir answered this

Plz like

Randhir answered this

Plz share

Silent Killer answered this

2 hours

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Akshat answered this

the answer will be 2 hours

-3

Akshat answered this

2 hrs would be the answer

-2

Jaguar answered this

2 hrs

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Chirag answered this

In cylinder, r=7cm=0.7m l=15km =15000m In tank, l=50m b=44m h=0.21m Vol.of water in tank=lbh =50*44*0.21 =462m³ Height of cylindrical pipe=Vol. / πr² =462/(0.07)²(22/7) =462/0.0154 =30000m Time = 30000/15000 = 2 hours

Abhishek Sharma answered this

answer

Abhishek Sharma answered this

answer

Abhishek Sharma answered this

answer s

Makbul Mehar answered this

????? 10th

Tiasha Patel answered this

44 hrs.

Disha Pandey answered this

Please find this answer

Vijaya answered this

Let rcm be the radius and h cm be the height of a pipe(cylinder),then r=7cm=7/10m and h=5km=5000m [Distance covered in 1 hr=height of pipe] Now,Volume of water that flows out of the circular pipe in 1hr =

Pankaj Kumar Ram answered this

Maths

Mukul Sachin Kabta answered this

Here's is the Answer which you wanted

Thanks
Regards
In cylinder,
r=7cm=0.7m l=15km b=15000m
In tank,
l=50m b=44m h=0.21m
Volume of water in tank= length x breadth x height =50 x 44 x 0.21 =462m³
Height of cylindrical pipe=Volume / πr² =462/(0.07)²(22/7) =462/0.0154 =30000m
Time = 30000/15000 = 2 hours

Megharaj Rathod answered this

yudha

Nirbahadur Karki answered this

Please find this answer

Sanjan answered this

Please find this answer