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 water is flowing at the rate of 7ms through a circular pipe whose internal diameter is 2cm into a cylindrical tank into a cylindrical tank of radius of base 40 cm determine the increase of water level in half hour

speed = 7m/s

d of pipe = 2 cm = 0.02 m

r of vessel = 40 cm 

t = 30 min = 30 * 60 = 1800 s

let height of water raised be h

thus, ATQ=>

vol. of water passing through pipe in 1/2 hr = vol. of water in vessel

distance = speed * time

                = 7 * 1800

                = 12600 m

now, pie * 0.01 * 0.01 * 12600 = pie * 0.4 * 0.4 * h

1.26 = 0.16 * h

so, h = 7.875 m = 7875 mm

hope this helps, thumbs up plz

  • 82
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speed = 7m/s

d of pipe = 2 cm = 0.02 m

r of vessel = 40 cm

t = 30 min = 30 * 60 = 1800 s

let height of water raised be h

thus, ATQ=

vol. of water passing through pipe in 1/2 hr = vol. of water in vessel

distance = speed * time

= 7 * 1800

= 12600 m

now,pie* 0.01 * 0.01 * 12600 =pie* 0.4 * 0.4 * h

1.26 = 0.16 * h

so, h = 7.875 m = 7875 mm

  • -3

Watet is flowing at the rate of 5 km per hour

  • -6
Length of water that flows out in 30 minutes
= (0.7 X 100 X 60 X 30) cm
= 126000 cm 
Volume of water that flows out in 30 minutes
=  (1)2 x 126000 cm3
= 126000  cm3
Let the depth of water in the tank be x cm
Volume of water in tank
=  (40)2 X x cm3
According to the question
 (40)2 X x = 126000
 x = 78.75 cm
  • -2
Length of water that flows out in 30 minutes = (0.7 X 100 X 60 X 30) cm = 126000 cm [ 1 ] Volume of water that flows out in 30 minutes =  (1)2 x 126000 cm3 = 126000  cm3 [1/2] Let the depth of water in the tank be x cm Volume of water in tank =  (40)2 X x cm3 [1/2] According to the question  (40)2 X x = 126000 [1/2]  x = 78.75 cm [1/2]
  • 2
h=7.875m=7875mm
  • -8
7875mm

 
  • -8
upper one is correct 
 
  • -14
why every ans different
  • -6
thanks a lot vibhav
 
  • -4
Speed of water = 7 m/s
​Diameter of pipe = 2 cm, Radius = 2/2 = 1 cm = 0.01 m = r
Radius of cylindrical tank = 40 cm = 0.4 m = R
​Time = 30 minutes = 30*60 s = 1800 s

​Therefore, volume passing through the pipe in half an hour = Volume of water raised in cylindrical tank

​But, distance of water travelled = speed * time = 7 * 1800 = 12600 m = h

​Let increase of water level be H.

​Therefore, pi*r^2*h = pi * R^2 * H
0.01*0.01*12600 = 0.4*0.4*H
​H = 7.875 m

 
  • 10
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