Wavelength of electron in Nanometer if its kinetic energy is 0.3 yJ
Dear student ,
Since the kinetic energy =
v = (2E / m)1/2 = = 0.257 x 1017 m /s
Now the wave length ( as per the de - Broglie's equqtion )
= 2.83 x 10-20 m or 2.83 x 10-11 nm
Regards
Since the kinetic energy =
v = (2E / m)1/2 = = 0.257 x 1017 m /s
Now the wave length ( as per the de - Broglie's equqtion )
= 2.83 x 10-20 m or 2.83 x 10-11 nm
Regards
