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what acute angle does a line of slope -2/3 make with vertical line.

$s l o p e o f l i n e, m = \frac{- 2}{3} m = \tan θ \Rightarrow \frac{- 2}{3} = \tan θ o r \tan θ = \frac{- 2}{3} \Rightarrow θ = \tan^{- 1} (\frac{3}{2}) N o w, l e t α b e a n a c u t e a n g l e . \Rightarrow α = 90^{0} - θ \Rightarrow α = 90^{0} - \tan^{- 1} (\frac{3}{2}) \Rightarrow α = 90^{0} - {56.3}^{0} \Rightarrow α = {33.6}^{0}$

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