what changes in the bond order in N2 and F2 occur when an electron is removed from both?

Dear Student,

Bond order is defined as the number of chemical bonds between two entities.

The MO diagram for F2 is:
http://www.austincc.edu/lgregory/Molecular%20Orbital%20Diagrams.htm
Number of electrons in bonding orbitals = 10
Number of electrons in antibonding orbitals = 8
Bond order = 1/2 x (10-8) = 1

In F2+ , an electron is removed from the pi*2pz orbital. 
Thus, bond order = 1/2 x (10-7) = 1.5

Thus, bond order is increased by 0.5 when an electron is removed from F2.

Similarly for N2,

Image result for molecular orbital diagram for n2
Number of bonding electrons = 10
Number of antibonding electrons = 4
Bond order for N2= 0.5 x (10-4) = 3

Now, in N2+, an electron is removed from sigma 2pz orbital.
Bond order = 0.5 x (9-4) = 2.5

Thus, the bond order decreases by 0.5 when an electron is removed from N2.



Hope it helps.

Regards

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