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what changes in the bond order in N_{2} and F_{2} occur when an electron is removed from both?

Bond order is defined as the number of chemical bonds between two entities.

The MO diagram for F

_{2}is:

Number of electrons in bonding orbitals = 10

Number of electrons in antibonding orbitals = 8

Bond order = 1/2 x (10-8) = 1

In F

_{2}

^{+}, an electron is removed from the pi

^{*}2p

_{z}orbital.

Thus, bond order = 1/2 x (10-7) = 1.5

Thus, bond order is increased by 0.5 when an electron is removed from F

_{2}.

Similarly for N

_{2},

Number of bonding electrons = 10

Number of antibonding electrons = 4

Bond order for N

_{2}= 0.5 x (10-4) = 3

Now, in N

_{2}

^{+}, an electron is removed from sigma 2p

_{z}orbital.

Bond order = 0.5 x (9-4) = 2.5

Thus, the bond order decreases by 0.5 when an electron is removed from N

_{2}.

Hope it helps.

Regards

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