what force is applied on a piston of area of cross section 2 cm square to obtain of force 150 Newton on the piston of area of cross section 12 centimetre square in a hydraulic machine. please answer it. Urgent

Dear Student,

We know that in a hydraulic machine, Pressure in equal on both sides.
Thus,

P1=P2F1A1=F2A2F12=15012F1=25 N

Regards

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