what happens when sodium acetate is heated with soda lime

When sodium acetate is treated with soda lime decarboxylation takes place and CO2 is eliminated from the sodium acetate . the chemical reaction can be written as

CH3COONa  +  NaOH -->  CH4  +  Na2CO3.

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"transpiration is a necessary evil"

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i) Sodium salt of caboxylic acid that is sodium actetate (CH3COONa) when heated with soda lime (NaOH - sodium hydroxide).A decaoboxylation reaction takes place that is carbon dioxide is removed or eliminated from CH3 COO Na  so to give product methane (CH4 ) and sodium carbonate ( Na2CO3 ), the equation for this reaction is :

 CH3COONa + NaOH  ---------> CH4  + Na2CO3

ii) 1) Transpiration is described as a necessary evil because it involves loss of water which is an essential compound for life.
 

2) Transpiration is said to be a necessary evil because it is an inevitable, but potentially harmful, consequence of the existence of wet cell surfaces form which evaporation occurs. Loss of water from the plant results wilting, serious desiccation and often death of a plant if a condition of drought is experienced. There is strong evidence that even mild water stress results in reduced growth rate and in crops to economic losses through reduction of yield.

3) Despite its apparent inevitability, transpiration is also of great significance for the plant .Water is conducted in most tall plants due to transpiration pull.

4) Minerals dissolved in water are distributed throughout plant body by transpiration stream.Evaporation of water from the exposed surface of cells of leaves has cooling effect on plant. Wet surface of leaf cells allow gaseous exchange.Transpiration affects indirectly the processes of respiration and photosynthesis.

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I GAVE MY LAST THUMBS UP TO YOU IN THE EARLIER PAGE

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WHAT IS THE ELECTRONIC CONFIGURATION OF SCANDIUM

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OR

Electronic configuration of Scandium = 2,8,9,2

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ISN'T IT 2,8,9,2

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Atomic no of Scandium = 21

Electronic configuration of Scandium = 2,8,8,3

 

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No coz dey r D-block elements and we have to learnd abt dem in 11th !!!!!

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DO WE GET TO IDENTIFY ELEMENTS IN GROUP3 TO GROUP 12

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the answer given by imad93 is wrong because soda lime isnt NaOH...............

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CH3COONa + NaOH   -------CaO--------> CH4 + Na2CO3

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