What is correct for 10 g of CaCO3 ?
i) It contains 1 g atom of carbon
ii) It contains 0.3 g atoms of oxygen 
iii) It contains 12 g of calcium
iv) It refers to 0.1 g equivalent of CaCO​3
 

Dear Student,

10 g CaCO3 contains C=12100×10=1.2 g of CTherefore, gramatom of C =1.212=0.1 gatom of C10 g CaCO3 contains 3O=3×16100×10=4.8 g of OTherefore, gramatom of O =4.816=0.3 gatom of O10 g of CaCO3 contains Ca=40100×10=4 g of CaMolecular mass of CaCO3=100 gmol-1Number of electrons involved, i.e. n=2Therefore, equivalent weight= 1002=50 g equiv-1Now, Equivalent=1050=0.2 equivHence, the correct answer is (ii)

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