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what is dy/dx when y=tan-1[5ax/a2-6x2]

here 2 represents the square

$y = \tan^{- 1} (\frac{5 a x}{a^{2} - 6 x^{2}}) = \tan^{- 1} (\frac{\frac{5 a x}{a^{2}}}{1 - 6 \frac{x^{2}}{a^{2}}}) = \tan^{- 1} (\frac{\frac{2 x}{a} + \frac{3 x}{a}}{1 - (\frac{2 x}{a}) (\frac{3 x}{a})}) = \tan^{- 1} (\frac{2 x}{a}) + \tan^{- 1} (\frac{3 x}{a}) \frac{d y}{d x} = (\frac{2}{a}) \times \frac{1}{1 + (\frac{2 x}{a})^{2}} + (\frac{3}{a}) \times \frac{1}{1 + {(\frac{3 x}{a})}^{2}} = \frac{2 a}{a^{2} + 4 x^{2}} + \frac{3 a}{a^{2} + 9 x^{2}}$

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